AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A swimming pool has depth of 3 meters. The pressure at the bottom of the pool due to water alone is (Density of water is \(1000 \mathrm{~kg} \mathrm{~m}^{-3}\), Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(10^4 \mathrm{~Pa}\)
- B \(3 \times 10^3 \mathrm{~Pa}\)
- C \(29 \times 10^3 \mathrm{~Pa}\)
- D \(30 \times 10^3 \mathrm{~Pa}\)
Answer & Solution
Correct Answer
(D) \(30 \times 10^3 \mathrm{~Pa}\)
Step-by-step Solution
Detailed explanation
Depth, \(\mathrm{h}=3 \mathrm{~m}\) density, \(\rho=10^3 \mathrm{~kg} / \mathrm{m}^3\) Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^2\) Pressure at bottom is given by…
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