AP EAMCET · PHYSICS · Current Electricity
In the circuit shown in figure, power developed across \(1 \Omega, 2 \Omega\) and \(3 \Omega\) resistances are in the ratio.
- A 1 : 2 : 3
- B 4 : 2 : 27
- C 6 : 4 : 9
- D 2 : 1 : 27
Answer & Solution
Correct Answer
(B) 4 : 2 : 27
Step-by-step Solution
Detailed explanation
Current distribution is as shown in figure \(\therefore\) Powers are \( \begin{aligned} & P_1=I_1^2 R_1=\frac{4}{9} i^2, P_2=I_2^2 R_2=\frac{2}{9} i^2, \text { and } P_3=I_3^2 R_3=3 i^2 \\ & =\frac{27}{9} i^2 . \\ & \Rightarrow \quad P_1: P_2: P_3:: 4: 2: 27 \end{aligned} \)
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