AP EAMCET · PHYSICS · Laws of Motion

A cricket ball of mass $50 g$ having velocity $50 cm s^{- 1}$ is stopped in $0.5 s$ . The force applied to stop the ball is

A $0.07 N$
B $0.05 N$
C $5 N$
D $7 N$

Verified Solution

Answer & Solution

Correct Answer

(B) $0.05 N$

Step-by-step Solution

Detailed explanation

Initial momentum of the ball is =50×10-3 kg×50×10-2 m s-1=25×10-3 kg m s-1 Final momentum =0 kg m s-1 Magnitude of force applied…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A cricket ball of mass 50 g having velocity 50 cm s-1 is stopped in 0.5 s. The force applied to stop the ball is

Step-by-step Solution

A cricket ball of mass $50 g$ having velocity $50 cm s^{- 1}$ is stopped in $0.5 s$ . The force applied to stop the ball is