AP EAMCET · PHYSICS · Current Electricity
In a potentiometer, a wire of length \(10 \mathrm{~m}\) having resistance \(50 \Omega\) is used. A battery of \(5 \mathrm{~V}\) and a resistor of \(450 \Omega\) are connected in series to the wire. If an unknown battery of emf \(E\) balances the potentiometer at \(450 \mathrm{~cm}\), then the value of \(E\) is
- A 0.225 V
- B 1.25 V
- C 2.25 V
- D 0.0225 V
Answer & Solution
Correct Answer
(A) 0.225 V
Step-by-step Solution
Detailed explanation
Given length of wire, \(l=10 \mathrm{~m}\), resistance of wire, \(R=50 \Omega\), emf of battery, \(E_1=5 \mathrm{~V}\), balancing length, \(x=450 \mathrm{~cm}=4.5 \mathrm{~m}\) series resistor, \(R_1=450 \Omega\) Current,…
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