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AP EAMCET · PHYSICS · Atomic Physics

Energy of a stationary electron in the hydrogen atom is E=-13.6n2eV then the energies required to excite the electron in hydrogen atom to (a) its second excited state and (b) ionized state respectively

  1. A (a) ~10eV, (b) 13.6eV
  2. B (a) ~12eV, (b) 13.6eV
  3. C (a) ~12eV, (b) 10.6eV
  4. D (a) ~8eV, (b) 13.6eV
Verified Solution

Answer & Solution

Correct Answer

(B) (a) ~12eV, (b) 13.6eV

Step-by-step Solution

Detailed explanation

(a) For Hydrogen atom, For ground state, n=1, energy is E1=-13.612=-13.6 eV For second excited state, n=3, Energy is E2=-13.632=-1.5 eV Energy required is ∆E=E2-E1=-1.5+13.6=12.1 eV≈12 eV (b) lonization energy is defined for ground state only, so…