AP EAMCET · PHYSICS · Capacitance
In a parallel plate capacitor the separation between plates is \(3 x\). This separation is filled by two layers of dielectrics, in which one layer has thickness \(x\) and dielectric constant \(3 k\), the other layer is of thickness \(2 x\) and dielectric constant \(5 k\). If the plates of the capacitor are connected to a battery, then the ratio of potential difference across the dielectric layers is
- A \(\frac{1}{2}\)
- B \(\frac{4}{3}\)
- C \(\frac{3}{5}\)
- D \(\frac{5}{6}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{6}\)
Step-by-step Solution
Detailed explanation
Key Idea Capacitance of a parallel plate capacitor is give by relation, \( C=\varepsilon_r \cdot \frac{\varepsilon_0 A}{d} \) where, \(\varepsilon_r=\) dielectric constant, \(A=\) area of parallel plate and \(d=\) distance between the plate. Here,…
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