AP EAMCET · PHYSICS · Thermodynamics
In a thermodynamic process the pressure of a fixed mass of a gas is changed in such a manner that the gas released \(30 \mathrm{~J}\) of heat and \(18 \mathrm{~J}\) of work was done on the gas. If the initial internal energy of the gas was \(60 \mathrm{~J}\), the final internal energy will be
- A \(32 \mathrm{~J}\)
- B \(48 \mathrm{~J}\)
- C \(72 \mathrm{~J}\)
- D \(96 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(48 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given that, heat released, \(\Delta Q=-30 \mathrm{~J}\) Work done on the gas, \(\Delta W=-18 \mathrm{~J}\) Change in internal energy \(=\Delta U\) Initial internal energy, \(U_i=60 \mathrm{~J}\) Let final internal energy, \(U_f=U\) By using first law of thermodynamics,…
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