AP EAMCET · Maths · Probability
For a binomial distribution with mean 6 and variance 2. Then, the value of P(X = 8) is
- A \(\frac{2^8}{3^8}\)
- B \(\frac{2^8}{3^7}\)
- C \(\frac{2^8}{3^9}\)
- D \(\frac{2}{3^7}\)
Answer & Solution
Correct Answer
(B) \(\frac{2^8}{3^7}\)
Step-by-step Solution
Detailed explanation
Given Mean = np = 6 … (i) Variance = npq = 2 where q = 1 − p … (ii) \(\Rightarrow 6 q=2 \quad\) \{using Eq. (i) in Eq. (ii) \(\}\) \(\begin{aligned} q & =1 / 3 \\ \Rightarrow p & =1-1 / 3=2 / 3\end{aligned}\) From Eq. (i), we get…
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