AP EAMCET · Chemistry · Electrochemistry
In the Kolbe electrolysis of sodium propanoate, the products \(\mathrm{X}\) and \(\mathrm{Y}\) are formed at respected electrodes. What are \(\mathrm{X}\) and \(\mathrm{Y}\) ?
- A \(\mathrm{X}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3\) at Cathode; \(\mathrm{Y}=\mathrm{H}_2\) at Anode
- B \(\mathrm{X}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3\) at Cathode; \(\mathrm{Y}=\mathrm{H}_2\) at Anode
- C \(\mathrm{X}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3\) at Anode; \(\mathrm{Y}=\mathrm{H}_2\) at Cathode
- D \(\mathrm{X}=\mathrm{CH}_3-\mathrm{CH}_3\) at Anode; \(\mathrm{Y}=\mathrm{H}_2\) at Cathode
Answer & Solution
Correct Answer
(C) \(\mathrm{X}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3\) at Anode; \(\mathrm{Y}=\mathrm{H}_2\) at Cathode
Step-by-step Solution
Detailed explanation
\(2 \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CO} \overline{\mathrm{O}^2} \mathrm{Na} \xrightarrow[2 \mathrm{H}_2 \mathrm{O}]{\text { electrolysis }}\) \[ \mathrm{CH}_3 \mathrm{CH}_2-\mathrm{CH}_2 \mathrm{CH}_3+2 \mathrm{CO}_2+\mathrm{H}_2+2 \mathrm{NaOH} \] At anode (oxidation): At…
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