AP EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C, \operatorname{cosec} A(\sin B \cdot \cos C+\cos B \cdot \sin C)\) equals to
- A \(\frac{c}{a}\)
- B \(\frac{a}{c}\)
- C \(1\)
- D \(\frac{a}{b}\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
Given, \(\operatorname{cosec} A(\sin B \cos C+\cos B \sin C)\) By sine rule's \(\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=k\) \(\sin A=k a, \sin B=k b, \sin C=k c\) \(\therefore \frac{1}{k a}(k b \cos C+c k \cos B)=\frac{1}{a}(b \cos C+c \cos B)\) \(=\frac{a}{a}=1\)…
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