AP EAMCET · PHYSICS · Alternating Current
If the emf of an AC source is given by \(6 \sin \omega t+4 \sin 2 \omega t \mathrm{~V}\), then the rms value of the emf is
- A \(\sqrt{10} \mathrm{~V}\)
- B \(\sqrt{26} \vee\)
- C \(\sqrt{32} \mathrm{~V}\)
- D \(\sqrt{20} \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{26} \vee\)
Step-by-step Solution
Detailed explanation
Given, emf of an AC source,…
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