AP EAMCET · Chemistry · Ionic Equilibrium
The solubility product of a sparingly soluble salt \(A_2 B\) is \(3.2 \times 10^{-11}\). Its solubility in \(\mathrm{mol} \mathrm{L}^{-1}\) is
- A \(4 \times 10^{-4}\)
- B \(2 \times 10^{-4}\)
- C \(6 \times 10^{-4}\)
- D \(3 \times 10^{-4}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
For the salt of type \(A_2 B\), solubility product \[ \left(K_{\mathrm{sp}}\right)=x^x \cdot y^y \cdot S^{x+y} \] where, \(x\) and \(y\) are the number of moles of \(A\) and \(B\) respectively. \[ S=\text { solubility. } \] Thus,…
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