AP EAMCET · PHYSICS · Thermodynamics
In a Carnot's engine if the temperatures of the source and the sink are decreased by \(100 \mathrm{~K}\) each then the efficiency of the engine
- A increases
- B decreases
- C remains constant
- D becomes one
Answer & Solution
Correct Answer
(A) increases
Step-by-step Solution
Detailed explanation
Initial efficiency is given by \(\eta=1-\frac{T_2}{T_1}=\frac{T_1-T_2}{T_1}\) Decreased by \(100 \mathrm{~K}\) each the efficiency \(\begin{aligned} & \eta=1-\frac{T_2-100}{T_1-100} \\ & =\frac{T_1-100-T_2+100}{T_1-100}=\frac{T_1-T_2}{T_1-100}\end{aligned}\)
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