AP EAMCET · PHYSICS · Thermal Properties of Matter
The wavelength of maximum emitted energy \(\left(\lambda_m\right)\) of a body at \(700 \mathrm{~K}\) is \(4.08 \mu \mathrm{m}\). If the temperature of the body is raised to \(1400 \mathrm{~K}\), then the value of \(\lambda_m\) will be
- A ) \(1.02 \mu \mathrm{m}\)
- B \(16.32 \mu \mathrm{m}\)
- C \(8.16 \mu \mathrm{m}\)
- D \(2.04 \mu \mathrm{m}\)
Answer & Solution
Correct Answer
(D) \(2.04 \mu \mathrm{m}\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} & \lambda_{m_1}=4.08 \mu \mathrm{m} \\ & T_1=700 \mathrm{~K} \\ & T_2=1400 \mathrm{~K} \\ & \lambda_{m_2}=\lambda_m=? \end{aligned} \] According to Wien's displacement law,…
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