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AP EAMCET · PHYSICS · Semiconductors

If \(R_C\) and \(R_B\) are respectively the resistances of in collector and base sides of the circuit, and \(\beta\) is the current amplification factor, then the voltage gain of a transistor amplifier in common emitter configuration is

  1. A \(\beta R_C R_B\)
  2. B \(\frac{\beta}{R_C R_B}\)
  3. C \(\frac{\beta R_B}{R_C}\)
  4. D \(\frac{\beta R_C}{R_B}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\beta R_C}{R_B}\)

Step-by-step Solution

Detailed explanation

The voltage gain of a CE configuration transistor is \(A_V=\frac{V_O}{V_I}=\frac{V_C}{V_B}=\frac{I_C R_C}{I_B R_B}=\left(\frac{I_C}{I_B}\right)\left(\frac{R_C}{R_B}\right)=\beta \cdot \frac{R_C}{R_B}\)