AP EAMCET · Maths · Straight Lines
If a straight line \(L\) perpendicular to the line \(3 x-4 y=6\) forms a triangle of area 6 square units with coordinate axes, then the minimum perpendicular distance from the point \((1,1)\) to the line \(\mathrm{L}\) is
- A 1
- B \(\sqrt{2}\)
- C 2
- D \(\sqrt{3}\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
The line which is perpendicular to the given line will have a slope of \(-\frac{4}{3}\). The equation of the line will look like \(3 y+4 x=k\). The line intersects the \(\mathrm{x}\)-axis at \(\left(\frac{\mathrm{k}}{4}, 0\right)\) an \(\mathrm{y}\)-axis at…
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