AP EAMCET · PHYSICS · Motion In Two Dimensions
If two stones are projected at angle ' \(\theta\) ' and \((90-\theta)\) respectively with horizontal with a speed of \(20 \mathrm{~ms}^{-1}\). If second stone rises 10 m higher than the first stone, then the angle of projection ' \(\theta\) ' is (acceleration clue to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(45^{\circ}\)
- B \(30^{\circ}\)
- C \(60^{\circ}\)
- D \(20^{\circ}\)
Answer & Solution
Correct Answer
(B) \(30^{\circ}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \quad \mathrm{u}=20 \mathrm{~ms}^{-1} \\ & \mathrm{H}_2=\mathrm{H}_1+10 \Rightarrow \frac{\mathrm{u}_2^2 \sin ^2\left(90^{\circ}-\theta\right)}{2 \mathrm{~g}}=\frac{\mathrm{u}_1^2 \sin ^2 \theta}{2 \mathrm{~g}}+10 \\ & \Rightarrow \frac{(20)^2 \cdot \cos ^2…
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