AP EAMCET · PHYSICS · Magnetic Effects of Current
A magnetic field intensity at the centre of a circular wire of radius \(0.1 \mathrm{~m}\) carrying a current \(0.2 \mathrm{~A}\) is
- A \(2 \pi \times 10^{-5} \mathrm{~T}\)
- B \(\pi \times 10^{-7} \mathrm{~T}\)
- C \(10^{-7} \mathrm{~T}\)
- D \(4 \pi \times 10^{-7} \mathrm{~T}\)
Answer & Solution
Correct Answer
(D) \(4 \pi \times 10^{-7} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Magnetic field intensity at the centre of a circular wire \(B=\frac{\mu_0 i}{2 r}=\frac{4 \pi \times 10^{-7} \times 0.2}{2 \times 0.1}=4 \pi \times 10^{-7} \mathrm{~T}\)
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