AP EAMCET · PHYSICS · Motion In Two Dimensions
If two bodies A and B are projected with same velocity but with different angles \(\theta_1\) and \(\theta_2\) respectively with the horizontal such that both will have same range, then the ratio of times of flight of the bodies A and B is
- A \(\sin \theta_2\)
- B \(\sin \theta_1\)
- C \(\tan \theta_2\)
- D \(\tan \theta_1\)
Answer & Solution
Correct Answer
(D) \(\tan \theta_1\)
Step-by-step Solution
Detailed explanation
\(T = \frac{2u \sin\theta}{g}\) \(\frac{T_A}{T_B} = \frac{2u \sin\theta_1 / g}{2u \sin\theta_2 / g} = \frac{\sin\theta_1}{\sin\theta_2}\) For same range, \(\theta_2 = 90^\circ - \theta_1\)…
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