AP EAMCET · PHYSICS · Kinetic Theory of Gases
If the internal energy of 3 moles of a gas at a temperature of \(27^{\circ} \mathrm{C}\) is 2250 R, then the number of degrees of freedom of the gas is
(R - Universal gas constant)
- A \(3\)
- B \(5\)
- C \(4\)
- D \(6\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
\(T = 27 + 273 = 300 \mathrm{~K}\) \(U = \frac{f}{2} nRT \Rightarrow 2250 R = \frac{f}{2} (3) R (300)\) \(2250 = 450 f \Rightarrow f = \frac{2250}{450} = 5\)
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