AP EAMCET · PHYSICS · Motion In Two Dimensions
If the height of a projectile at a time of 2 s from the beginning of motion is 60 m, then the time of flight of the projectile is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 12 s
- B 4 s
- C 6 s
- D 8 s
Answer & Solution
Correct Answer
(D) 8 s
Step-by-step Solution
Detailed explanation
\(h = u_y t - \frac{1}{2}gt^2\) \(60 = u_y (2) - \frac{1}{2}(10)(2)^2\) \(60 = 2u_y - 20\) \(2u_y = 80 \Rightarrow u_y = 40 \text{ m/s}\) \(T = \frac{2u_y}{g}\) \(T = \frac{2(40)}{10}\) \(T = 8 \text{ s}\)
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