AP EAMCET · PHYSICS · Thermal Properties of Matter
\(300 \mathrm{~g}\) of water at \(25^{\circ} \mathrm{C}\) is added to \(100 \mathrm{~g}\) of ice at \(0^{\circ} \mathrm{C}\). The final temperature of mixture will be
- A \(25^{\circ} \mathrm{C}\)
- B \(0^{\circ} \mathrm{C}\)
- C \(12.5^{\circ} \mathrm{C}\)
- D \(30^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(0^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given, mass of water \(m_w=300 \mathrm{~g}\) Temperature of water, \(T_w=25^{\circ} \mathrm{C}\) Mass of ice, \(\begin{gathered} m_i=100 \mathrm{~g} \\ T_i=0^{\circ} \mathrm{C} \end{gathered}\) Heat required to convert the ice at \(0^{\circ} \mathrm{C}\) to water at…
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