AP EAMCET · PHYSICS · Thermal Properties of Matter
If the cold junction is held at \(0^{\circ} \mathrm{C}\), the same thermo emf \(V\) of a thermocouple varies as \(V=10 \times 10^{-6} t-\frac{1}{40} \times 10^{-6} t^2\), where \(t\) is the temperature of the hot junction in \({ }^{\circ} \mathrm{C}\). The neutral temperature and the maximum value of thermo emf are respectively :
- A \(200^{\circ} \mathrm{C} ; 2 \mathrm{mV}\)
- B \(400^{\circ} \mathrm{C} ; 2 \mathrm{mV}\)
- C \(100^{\circ} \mathrm{C} ; 1 \mathrm{mV}\)
- D \(200^{\circ} \mathrm{C} ; 1 \mathrm{mV}\)
Answer & Solution
Correct Answer
(D) \(200^{\circ} \mathrm{C} ; 1 \mathrm{mV}\)
Step-by-step Solution
Detailed explanation
Given, \(V=10 \times 10^{-6} t-\frac{1}{40} \times 10^{-6} t^2\) At neutral temperature \(\frac{d V}{d t}=0\) \(\therefore \quad 10 \times 10^{-6}-\frac{1}{20} \times 10^{-6} t_n=0\) or \(\quad t_n=200^{\circ} \mathrm{C}\) Also at neutral temperature, thermo emf is maximum.…
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