AP EAMCET · Maths · Complex Number
If \(x\) is a cube root of unity other than 1 , then \(\left(x+\frac{1}{x}\right)^2+\left(x^2+\frac{1}{x^2}\right)^2+\ldots+\left(x^{12}+\frac{1}{x^{12}}\right)^2=\)
- A 12
- B 64
- C 24
- D 0
Answer & Solution
Correct Answer
(C) 24
Step-by-step Solution
Detailed explanation
Given, \(x\) is a cube root of unity other than 1 i.e. \(x=\omega\) or \(\omega^2\) Now…
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