AP EAMCET · PHYSICS · Units and Dimensions
If speed of light in vacuum \(\left(3 \times 10^8 \mathrm{~ms}^{-1}\right)\), acceleration due to gravity \(\left(10 \mathrm{~ms}^{-2}\right)\) and mass of electron \(\left(9.1 \times 10^{-31} \mathrm{~kg}\right)\) are taken as fundamental physical quantities, then the unit of time in this system is
- A \(3 \times 10^3 \mathrm{~s}\)
- B \(5 \times 10^{-19} \mathrm{~s}\)
- C \(3 \times 10^{19} \mathrm{~s}\)
- D \(3 \times 10^7 \mathrm{~s}\)
Answer & Solution
Correct Answer
(D) \(3 \times 10^7 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Speed of light, \(\left[\mathrm{L} \mathrm{T}^{-1}\right]=3 \times 10^8 \mathrm{~m} / \mathrm{s}\) ... (1) acceleration due to gravity, \(\left[\mathrm{L} \mathrm{T}^{-2}\right]=10 \mathrm{~m} / \mathrm{s}^{-2}\) ... (2) Divide equation (1) by (2), we have…
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