AP EAMCET · Maths · Permutation Combination
The number of six digit natural numbers that can be formed with the digits \(2,3,4,0,5,6,7,8\) is
- A \(7 \times 2^{12}\)
- B \(7 \times 2^9\)
- C \(7 \times 2^6\)
- D \(7 \times 2^{15}\)
Answer & Solution
Correct Answer
(D) \(7 \times 2^{15}\)
Step-by-step Solution
Detailed explanation
Given the digit 2, 3, 4, 0, 5, 6, 7, 8 So, number of 6 digit number \(\begin{aligned} & =7 \times 8 \times 8 \times 8 \times 8 \times 8 \\ & =7 \times 2^{15} \end{aligned}\)
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