AP EAMCET · PHYSICS · Gravitation
Find the angular speed of rotation of the Earth, so that the apparent \(g\) at the equator becomes (1/6)th of its original value.
\[
\left(R=6.4 \times 10^6 \mathrm{~m}\right)
\]
- A \(1.3 \times 10^{-6} \mathrm{rad} \mathrm{s}^{-1}\)
- B \(8.75 \times 10^{-4} \mathrm{rad} \mathrm{s}^{-1}\)
- C \(1.14 \times 10^{-3} \mathrm{rad} \mathrm{s}^{-1}\)
- D \(2.6 \times 10^6 \mathrm{rad} \mathrm{s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(1.14 \times 10^{-3} \mathrm{rad} \mathrm{s}^{-1}\)
Step-by-step Solution
Detailed explanation
The apparent \(g^{\prime}\) due to rotation of earth is given by \(g^{\prime}=g_0-\omega^2 R\)…
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