AP EAMCET · Chemistry · Chemical Kinetics
For a first order reaction, the concentration of reactant was reduced from \(0.03 \mathrm{~mol} \mathrm{~L}^{-1}\) to \(0.02 \mathrm{~mol} \mathrm{~L}^{-1}\) in 25 min . What is its rate (in \(\left.\mathrm{mol} \mathrm{L}^{-1}, s^{-1}\right)\) ?
- A \(6.667 \times 10^{-6}\)
- B \(4 \times 10^{-4}\)
- C \(6.667 \times 10^{-4}\)
- D \(4 \times 10^{-6}\)
Answer & Solution
Correct Answer
(A) \(6.667 \times 10^{-6}\)
Step-by-step Solution
Detailed explanation
Given :- Time \(=25 \times 60 \mathrm{sec} .=25 \mathrm{~min}\) Concentration of Reactant \(=0.03 \mathrm{~mol} \mathrm{~L}^{-1}\) Concentration of product \(=0.02 \mathrm{~mol} \mathrm{~L}^{-1}\) Rate…
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