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AP EAMCET · PHYSICS · Electrostatics

Electric field vector in a region is given by \(\mathbf{E}=(3 \hat{\mathbf{i}}+4 y \hat{\mathbf{j}}) \mathrm{V}-\mathrm{m}^{-1}\). The potential at the origin is zero. Then, the potential at a point \((2,1) \mathrm{m}\) is

  1. A 7 V
  2. B 8 V
  3. C -8 V
  4. D -7 V
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Answer & Solution

Correct Answer

(C) -8 V

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Detailed explanation

\begin{gathered} \text { As, } \quad E=\frac{-\partial V_x}{\partial x} \hat{\mathrm{i}}+\frac{-\partial V_y}{\partial y} \hat{\mathrm{j}} \\ \frac{-\partial V_x}{\partial x}=3 \text { and } \frac{-\partial V_y}{\partial y}=4 y \\ \Rightarrow \quad V_x=-3 x \text { and } V_y=-2…

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