AP EAMCET · Maths · Pair of Lines
The lines \(3 x^2+8 x y-3 y^2+2 x-4 y-1=0\) and \(4 x-3 y-2=0\)
- A form an equilateral triangle
- B form a right angled triangle
- C form a right angled isosceles triangle
- D are concurrent
Answer & Solution
Correct Answer
(D) are concurrent
Step-by-step Solution
Detailed explanation
\( \frac{\partial}{\partial x}(3 x^2+8 x y-3 y^2+2 x-4 y-1) = 6x + 8y + 2 = 0 \implies 3x + 4y + 1 = 0 \) \( \frac{\partial}{\partial y}(3 x^2+8 x y-3 y^2+2 x-4 y-1) = 8x - 6y - 4 = 0 \implies 4x - 3y - 2 = 0 \) The second partial derivative equation is identical to the second…
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