AP EAMCET · PHYSICS · Mechanical Properties of Solids
Depth of a river is 100 m . Magnitude of compressibility of the water is \(0.5 \times 10^{-9} \mathrm{~N}^{-1} \mathrm{~m}^2\). The fractional compression in water at the bottom of the river is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(0.9 \times 10^3\)
- B \(0.5 \times 10^3\)
- C \(2 \times 10^{-3}\)
- D \(1.3 \times 10^{-2}\)
Answer & Solution
Correct Answer
(B) \(0.5 \times 10^3\)
Step-by-step Solution
Detailed explanation
Compressibility, \(\mathrm{k}=0.5 \times 10^{-9} \mathrm{~N}^{-1} \mathrm{~m}^2\) Pressure, \(\mathrm{P}=\delta \mathrm{gh}=10^3 \times 10 \times 100=10^6 \mathrm{Nm}^{-2}\) \(\therefore \mathrm{K}=\frac{1}{\mathrm{~B}}=\frac{(\Delta \mathrm{v} / \mathrm{v})}{\mathrm{P}}\)…
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