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AP EAMCET · Maths · Properties of Triangles

In \(\triangle \mathrm{ABC}\), if \(b=2, c=\sqrt{3},\left\lfloor\mathrm{~A}=30^{\circ}\right.\), then its inradius \(r=\)

  1. A \(\sqrt{3}-1\)
  2. B \(\sqrt{3}+1\)
  3. C \(\frac{\sqrt{3}+1}{2}\)
  4. D \(\frac{\sqrt{3}-1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\sqrt{3}-1}{2}\)

Step-by-step Solution

Detailed explanation

\(a^2 = b^2 + c^2 - 2bc \cos A = 2^2 + (\sqrt{3})^2 - 2(2)(\sqrt{3}) \cos 30^{\circ} = 4+3-6 = 1\) \(a = 1\) \(K = \frac{1}{2}bc \sin A = \frac{1}{2}(2)(\sqrt{3}) \sin 30^{\circ} = \frac{\sqrt{3}}{2}\) \(s = \frac{a+b+c}{2} = \frac{1+2+\sqrt{3}}{2} = \frac{3+\sqrt{3}}{2}\)…