AP EAMCET · PHYSICS · Magnetic Effects of Current
Consider a tightly wound 100 turn coil of radius \(10 \mathrm{~cm}\) carrying a current of \(2 \mathrm{~A}\). The magnitude of the magnetic field at the centre of the coil is
- A \(3.14 \times 10^{-4} \mathrm{~T}\)
- B \(6.28 \times 10^{-4} \mathrm{~T}\)
- C \(12.56 \times 10^{-4} \mathrm{~T}\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(12.56 \times 10^{-4} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Number of turns \(n=100\) Radius, \(r=10 \mathrm{~cm}=0.1 \mathrm{~m}\) current, \(\mathrm{I}=2 \mathrm{~A}\) Magnetic field at center of coil:…
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