AP EAMCET · PHYSICS · Motion In One Dimension
A car moving with uniform acceleration covers the distance of \(200 \mathrm{~m}\) in first 2 seconds and the distance of \(220 \mathrm{~m}\) in next 4 seconds. The velocity of the car after 7 seconds is
- A \(10 \mathrm{~ms}^{-1}\)
- B \(20 \mathrm{~ms}^{-1}\)
- C \(15 \mathrm{~ms}^{-1}\)
- D \(30 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(10 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Distance travelled in first 2 seconds \(=200 \mathrm{~m}\) \(S=u t+\frac{1}{2} a t^2\) \(200=2 u+\frac{1}{2} \times a \times 2^2\) \(u+a=100\) ...(1) Distance travelled in next 4 seconds \(=220 \mathrm{~m}\) Total distance travelled in first 6 second \(=420 \mathrm{~m}\)…
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