AP EAMCET · Maths · Permutation Combination
The sum of all possible numbers that can be formed by using the digits \(2,3,5,7\) without repetition of digits is
- A \(17 \times \frac{10^4-1}{9}\)
- B \(33 \times 34 \times 101\)
- C \(6 \times \frac{10^3-1}{9}\)
- D \(33 \times 35 \times 1001\)
Answer & Solution
Correct Answer
(B) \(33 \times 34 \times 101\)
Step-by-step Solution
Detailed explanation
Sum \[ \begin{aligned} & =3 ! \times(2+3+5+7) \times(1000+100+10+1) \\ & =6 \times 17 \times 1111 \\ & =33 \times 34 \times 101 \end{aligned} \]
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