AP EAMCET · PHYSICS · Mechanical Properties of Fluids
The gauge pressure at a depth of \(50 \mathrm{~m}\) in a sea is (Density of sea water is \(1025 \mathrm{~kg} \mathrm{~m}^{-3}\) and \(\mathrm{g}=10 \mathrm{~ms}^{-2}\) )
- A \(1025 \mathrm{~Pa}\)
- B \(512500 \mathrm{~Pa}\)
- C \(20000 \mathrm{~Pa}\)
- D \(15000 \mathrm{~Pa}\)
Answer & Solution
Correct Answer
(B) \(512500 \mathrm{~Pa}\)
Step-by-step Solution
Detailed explanation
The gauge pressure at a depth of \(50 \mathrm{~m}\), \(\begin{aligned} & P=\rho g h \\ & =1025 \times 10 \times 50 \\ & =512500 \mathrm{~Pa} \end{aligned}\)
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