AP EAMCET · PHYSICS · Rotational Motion
As shown in the figure, two thin coplanar circular discs \(A\) and \(B\) each of mass ' \(M\) ' and radius ' r ' are attached to form a rigid body. The moment of inertia of this system about an axis perpendicular to the plane of disc \(B\) and passing through its centre is
- A \(2 \mathrm{Mr}^2\)
- B \(3 \mathrm{Mr}^2\)
- C \(4 \mathrm{Mr}^2\)
- D \(5 \mathrm{Mr}^2\)
Answer & Solution
Correct Answer
(D) \(5 \mathrm{Mr}^2\)
Step-by-step Solution
Detailed explanation
\(I_B = \frac{1}{2}Mr^2\) \(I_A = \frac{1}{2}Mr^2 + M(2r)^2 = \frac{9}{2}Mr^2\) \(I_{total} = I_B + I_A = \frac{1}{2}Mr^2 + \frac{9}{2}Mr^2 = 5Mr^2\)
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