AP EAMCET · PHYSICS · Electromagnetic Waves
An electromagnetic wave of frequency \(2 \mathrm{MHz}\) propagates from vacuum to a non-magnetic medium of relative permittivity 9 . Then its' wavelength
- A increases by 100 m
- B increases by 50 m
- C decreases by 50 mm
- D decreases by 100 m
Answer & Solution
Correct Answer
(D) decreases by 100 m
Step-by-step Solution
Detailed explanation
In vacuum wavelength, \(\lambda_0=\frac{c}{f_0}=\frac{3 \times 10^8}{2 \times 10^6}=1.5 \times 10^2=150 \mathrm{~m}\) In medium, speed of wave is \(v=\frac{\mathcal{c}}{\sqrt{\varepsilon_r \mu_r}} \approx \frac{\mathcal{c}}{\sqrt{\varepsilon_r}}\) (as medium is non-magnetic)…
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