AP EAMCET · PHYSICS · Work Power Energy
An object of mass \(20 \mathrm{~kg}\). is displaced by \(x=5 t^2 \mathrm{~m}\) (here \(t\) is time) by the application of a force. Then the ratio of the work done in times \(3 \mathrm{~s}\) and \(5 \mathrm{~s}\) is
- A \(2 / 3\)
- B \(4 / 9\)
- C \(3 / 5\)
- D \(9 / 25\)
Answer & Solution
Correct Answer
(D) \(9 / 25\)
Step-by-step Solution
Detailed explanation
( Given, displacement of block, \(x=5 t^2\) As, velocity \(v=\frac{d x}{d t}\) Velocity of block, \(v=\frac{d}{d t}\left(5 t^2\right)\) \[ =5 \times 2 t=10 t \mathrm{~m} / \mathrm{s} \] Now, velocity of block at \(t=5 \mathrm{~s}\),…
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