AP EAMCET · PHYSICS · Electrostatics
The minimum work needed to be done to bring a charge \(q=6 \mu \mathrm{C}\) from \(\infty\) to a point \(0.75 \mathrm{~m}\) from a charge \(Q=30 \mu \mathrm{C}\) is
- A \(4.16 \mathrm{~J}\)
- B \(5.16 \mathrm{~J}\)
- C \(2.16 \mathrm{~J}\)
- D \(1.16 \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(2.16 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given, first charge, \(q=6 \mu \mathrm{C}\) \[ =6 \times 10^{-6} \mathrm{C} \] Charge, \(Q=30 \mu \mathrm{C}\) \[ =30 \times 10^{-6} \mathrm{C} \] Final distance, \(r_f=0.75 \mathrm{~m}\) Initial distance, \(r_i=\infty\) Since, work…
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