AP EAMCET · Maths · Application of Derivatives
Find the equation of the normal to the curve \(y=\frac{(x-7)}{(x-2)(x-3)}\) at the point where it cuts the \(X\)-axis.
- A \(20 x+y+140=0\)
- B \(x-20 y-140=0\)
- C \(x+20 y+140=0\)
- D \(20 x+y-140=0\)
Answer & Solution
Correct Answer
(D) \(20 x+y-140=0\)
Step-by-step Solution
Detailed explanation
Given curve, \(y=\frac{(x-7)}{(x-2)(x-3)}\),cuts the \(x\)-axis at point \(P(7,0)\).…
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