AP EAMCET · PHYSICS · Thermodynamics
An ideal heat engine has an efficiency \(\eta\). The coefficient of performance of the engine when driven backward will be
- A \(1-\left(\frac{1}{\eta}\right)\)
- B \(\eta-\left(\frac{1}{\eta}\right)\)
- C \(\left(\frac{1}{\eta}\right)-1\)
- D \(\frac{1}{1-\eta}\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{1}{\eta}\right)-1\)
Step-by-step Solution
Detailed explanation
For ideal heat engine, efficiency is given as \(\begin{array}{ll} & \eta=\frac{W}{Q_1}=\frac{Q_1-Q_2}{Q_1} \\ \Rightarrow & \eta=1-\frac{Q_2}{Q_1}=1-\frac{T_2}{T_1} \end{array}\)…
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