AP EAMCET · PHYSICS · Thermodynamics
An ideal gas has specific heat capacity at constant pressure \(\frac{11}{10} R\). If one mole of this ideal gas at \(125^{\circ} \mathrm{C}\) does \(83 \mathrm{~J}\) of work adiabatically, then the final temperature of the gas would be (Universal gas constant, \(R=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\) )
- A \(25^{\circ} \mathrm{C}\)
- B \(50^{\circ} \mathrm{C}\)
- C \(75^{\circ} \mathrm{C}\)
- D \(100^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(25^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Work done by gas in adiabatic process, \(\Delta W=+83 \mathrm{~J}\) As in adiabatic process, \(\Delta Q=0\), By first law of thermodynamics, \(\Delta Q=\Delta U+\Delta W\) so change in internal energy of gas, \(\Delta U=-83 \mathrm{~J}\) Also, \(\Delta U=n C_V \Delta T=83\)…
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