AP EAMCET · Maths · Permutation Combination
If \(x\) is the number of ways in which six women and six men can be arranged to sit in a row such that no two women are together and if \(y\) is the number of ways they are seated around a table in the same manner, then \(x: y=\)
- A \(12: 1\)
- B \(42: 1\)
- C \(16: 1\)
- D \(6: 1\)
Answer & Solution
Correct Answer
(B) \(42: 1\)
Step-by-step Solution
Detailed explanation
6 Boys can be seated in a row in \(6_{P_6}\) ways \(=6 !\). Now, in the 7 gaps 6 girls can be arranged in \(7_{P_6}\) ways. \[ \therefore \quad x=6 ! \times 7_{P_6}=6 ! \times 7 ! \] 6 Boys can be seated in a circle in \[ (6-1) \text { ! ways }=5 \text { ! } \] Now, in the 6…
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