AP EAMCET · PHYSICS · Semiconductors
A Zener diode of breakdown voltage 20 V is connected as shown in the given circuit. The current through Zener diode is
- A 10 mA
- B 4 mA
- C 6 mA
- D 8 mA
Answer & Solution
Correct Answer
(C) 6 mA
Step-by-step Solution
Detailed explanation
\(I_S = \frac{V_{in} - V_Z}{R_S}\) \(I_S = \frac{30 \text{ V} - 20 \text{ V}}{1000 \text{ } \Omega} = \frac{10 \text{ V}}{1000 \text{ } \Omega} = 0.01 \text{ A} = 10 \text{ mA}\) \(I_L = \frac{V_Z}{R_L}\)…
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