AP EAMCET · Maths · Continuity and Differentiability
Let \(\mathrm{f}: \mathbb{R} \rightarrow \mathbb{R}\) be defined by
\(f(x)=\left\{\begin{array}{cl}a-\frac{\sin [x-1]}{x-1} &, \text { if } x>1 \\ 1 &, \text { if } x=1 \\ b-\left[\frac{\sin [x-1]-[x-1]}{\left.([x-1])^3\right]}\right] &, \text { if } x < 1\end{array}\right.\)
where \([t]\) denotes the greatest integer less than or equal to \(t\). If \(f\) is continuous at \(\mathrm{x}=1\), then \(\mathrm{a}+\mathrm{b}=\)
- A 0
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
For continuity at \(x=1\): \(\lim_{x \to 1^+} f(x) = f(1) = \lim_{x \to 1^-} f(x)\) \(f(1) = 1\) \(\lim_{x \to 1^+} f(x) = \lim_{x \to 1^+} \left(a - \frac{\sin [x-1]}{x-1}\right)\) As \(x \to 1^+\), \(x-1 \to 0^+\), so \([x-1] = 0\).…
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