AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A uniform circular disc has radius \(r\). A square portion of diagonal \(r\) is cut from it. The centre of mass of the remaining disc from the centre of disc is
- A \(\frac{r}{2-4 \pi}\)
- B \(\frac{r}{3-3 \pi}\)
- C \(\frac{r}{2-5 \pi}\)
- D \(\frac{2 r}{1-2 \pi}\)
Answer & Solution
Correct Answer
(A) \(\frac{r}{2-4 \pi}\)
Step-by-step Solution
Detailed explanation
Suppose, the mass of circular disc is \(M\). A square portion of diagonal \(r\) is cut from it. Assuming centre of mass of circle to be origin. Centre of mass of square portion will be at distance \(\frac{r}{2}\) from it. \(\therefore\) Side of square \(=\frac{r}{\sqrt{2}}\)…
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