AP EAMCET · PHYSICS · Magnetic Effects of Current
A circular loop and an infinitely long straight conductor carry equal currents, as shown in the figure. The net magnetic field at the centre of the loop is \(B_1\), when the current in the loop is clockwise and \(B_2\) when the current in the loop is anti-clockwise. Then \(\frac{B_1}{B_2}\) is
- A \(\frac{15}{29}\)
- B \(\frac{13}{15}\)
- C \(\frac{13}{17}\)
- D \(\frac{17}{19}\)
Answer & Solution
Correct Answer
(A) \(\frac{15}{29}\)
Step-by-step Solution
Detailed explanation
When current is clockwise, then net magnetic field, \[ B_1=\frac{\mu_0 i}{2 r}-\frac{\mu_0 i}{2 \pi r} \Rightarrow B_1=\frac{\mu_0 i}{2 r}\left(1-\frac{1}{\pi}\right) \] Similarly, when current is anti-clockwise \[ B_2=\frac{\mu_0 i}{2 r}\left(1+\frac{1}{\pi}\right) \] Now,…
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