AP EAMCET · PHYSICS · Mechanical Properties of Solids
If a pressure of \(8 \times 10^8 \mathrm{~N} \mathrm{~m}^{-2}\) is applied to a lead block, so that its volume reduces by \(20 \%\). The Bulk modulus of lead block is
- A \(4 \times 10^7 \mathrm{Nm}^{-2}\)
- B \(4 \times 10^8 \mathrm{Nm}^{-2}\)
- C \(4 \times 10^9 \mathrm{Nm}^{-2}\)
- D \(4 \times 10^{10} \mathrm{Nm}^{-2}\)
Answer & Solution
Correct Answer
(C) \(4 \times 10^9 \mathrm{Nm}^{-2}\)
Step-by-step Solution
Detailed explanation
Pressure applied on the block, \(p=8 \times 10^8 \mathrm{Nm}^{-2}\) If \(V_1\) be initial volume, then final volume of block, \(\begin{aligned} & V_2=V_1-20 \% \text { of } V_1=V_1-\frac{20}{100} V_1 \\ & V_2=\frac{4}{5} V_1 \end{aligned}\) \(\therefore\) Change in volume,…
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