AP EAMCET · PHYSICS · Alternating Current
A resistor of resistance \(40 \Omega\), a capacitor of capacitive \(20 \Omega\) and an inductor of inductive reactance \(50 \Omega\) are connected in series to an ac source of \(100 \mathrm{~V}\). The current through the circuit is
- A \(0.5 \mathrm{~A}\)
- B \(1 \mathrm{~A}\)
- C \(1.5 \mathrm{~A}\)
- D \(2 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(2 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
The current through the circuit as \[ \begin{aligned} & i=\frac{V}{Z} \\ & =\frac{V}{\sqrt{R^2+\left(X_L-X_C\right)^2}}=\frac{100}{\sqrt{(0)^2+(50-120)^2}} \\ & =\frac{100}{\sqrt{1600+900}}=2 A \end{aligned} \]
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